Forces...

[crackoff]

Below is a very simplified diagram. I have been looking through lots of pages to find out the forces involved at differing points on this pic, but nowhere I have looked explains the force at B. By my reckoning, A should be working as would a fixed point in a 2-1 pulley system, the weight should be working as the pull/effort in the set up, which would make B the effective weight of the pull/effort x 2??? Is that correct?

 

Please note that although the pulley at B is fixed to the tree, it is the force on the tree that I want. thanks in advance.

 

[Pete Mctree]

If one ton is suspended from the pulley, an equivilant force is acting on the fixed point to keep it motionless.

So you are correct - a one ton load on either leg will place a load of 2 tons onthe pulley - doubling it

[Stephen Blair]

I would say a ton going up, a ton going down.

So x2, i sm no expert though.

[crackoff]

Thanks Pete... Always thought that was the case, but then got questioned about it today and really couldn't work it out...

[Dan Earp]

Yep two tons bud

[crackoff]

Cheers Dan... And thanks for the chat last night.

[Dan Earp]

Cheers Dan... And thanks for the chat last night.

 

Lol no problem 👍

[teepeeat]

2 ton + friction in the system

 

 

i'll get my coat

[Ian Flatters]

No one mentioned the force at fixed point A then?

[teepeeat]

No one mentioned the force at fixed point A then?

 

Fair comment Ian - I'd go for half of that at point B