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Posted

Any one here good at maths and equations?

 

Pen and paper at the ready.

 

Sweet chestnut, 10 metres length, with the total weight of the stripped stem weighing 2.5 T on a slope of 40 degrees.

 

The hung up tree leans down the slope at 50 degrees.

 

The wire to pull the top of tree back up the slope, i.e. towards the top of the hill, will have an angle of 30 degrees.

 

All angles are from a horizontal plane.

 

Anchor point 25 metres from wire attachment point on hung up tree.

 

There will be no resistance from root plate, but some from hinge.

 

So, how much force (pull) will be needed to lift tree to an upright position?

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Posted

45000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 and 1 N.

 

thankyou, where do i pick my prize up from?

Posted

At a wild guess I would say something leaning out at 45 degrees would have 50% of it's weight on the pivot point (root) and 50% on whatever is holding it up.

 

Therefore if you use a 2 ton winch you are allowing for any resistance or error.

 

All I would do is put in a 5 to one fiddle block one way system to hold the trunk in place should the winch fail :001_smile:

Posted

just get the biggest winch you can get your hands on and the biggest strops as well. can you be 100% sure of the weights and angles, where is the root plate going to go once you have pulled it over(i presume its windblown)

Posted
45000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 and 1 N.

 

thankyou, where do i pick my prize up from?

 

No prize; your'e one o out.

Posted
At a wild guess I would say something leaning out at 45 degrees would have 50% of it's weight on the pivot point (root) and 50% on whatever is holding it up.

 

Therefore if you use a 2 ton winch you are allowing for any resistance or error.

 

All I would do is put in a 5 to one fiddle block one way system to hold the trunk in place should the winch fail :001_smile:

 

Thanks Dean, that wild guess sounds good to me. Using a 3.5 T winch system, plenty of margin...

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