To some of the more learned members of this forum.

[Paper Rustler]

Perhaps I am being dumb here if I have 8kg of timber at 32% moisture how do I calculate the weight at 11% moisture, is it just simple arithmetic calculation or is there another way?

[Stephen Blair]

8000g divided by 32 (250) then times it by 11 =2.75kg

Edited October 2, 2009 by Stephen Blair

[skyhuck]

is it just simple arithmetic calculation

 

Yes

[Rupe]

8000kg divided by 32 (250) then times it by 11 =2.75kg

 

Only8 Kgs to start with!!

 

Thats not right htough, its only the moisture that has changed in weight not the wood. So with the calc above the 2.75kg is the reduction in weight then taken away from the original to leave 5.25kgs

 

Oh you edited already! Correct 8000g.

[Kev Stephenson]

32%-11% = weight lost by drying = 21%

 

21% of your original 8kg = 1.68kg lost

 

New weight = 8kg - 1.68kg = 6.32kg

[Dean Lofthouse]

The percentage is of the dry weight of the log.

 

A dry log weighing 1kg when bone dry will weigh 1.2kg with 20% moisture.

 

So you have to do a reverse calculation other wise it works out wrong.

 

The above calcs would mean a wet log weighing 1'2kg minus 20% moisture would weigh 0.96kg

[Rupe]

I'm wrong but the above is still not right.

 

weight lost by drying is not 21%, then 21% of the original etc etc, because that assumes the 21% lost was lost from the whole mass of wood, when in fact it was only lost from the moisture content part of it.

 

So it 21% lost from the 32% that was moisture??

[Stephen Blair]

Only8 Kgs to start with!!

 

Thats not right htough, its only the moisture that has changed in weight not the wood. So with the calc above the 2.75kg is the reduction in weight then taken away from the original to leave 5.25kgs

 

Oh you edited already! Correct 8000g.

 

surely the reduction in weight is the 5.25kg:confused1:

[Rupe]

Yes dean is closer, I was referring to STS

[Dean Lofthouse]

I've got brain ache